0=250x^2+10x-119

Solution for 0=250x^2+10x-119 equation:

0=250x^2+10x-119

We move all terms to the left:

0-(250x^2+10x-119)=0

We add all the numbers together, and all the variables

-(250x^2+10x-119)=0

We get rid of parentheses

-250x^2-10x+119=0

a = -250; b = -10; c = +119;
Δ = b2-4ac
Δ = -102-4·(-250)·119
Δ = 119100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{119100}=\sqrt{100*1191}=\sqrt{100}*\sqrt{1191}=10\sqrt{1191}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10\sqrt{1191}}{2*-250}=\frac{10-10\sqrt{1191}}{-500}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10\sqrt{1191}}{2*-250}=\frac{10+10\sqrt{1191}}{-500}
$